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Question
The number of bytes occupied by a character array of four rows and three columns is ______.
Options
12
24
96
48
MCQ
Fill in the Blanks
Solution
The number of bytes occupied by a character array of four rows and three columns is 24.
Explanation:
- The size of the char data type is 2 bytes.
- Thus, 2 * 4 * 3 = 24.
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RELATED QUESTIONS
Consider the following two-dimensional array and answer the questions given below:
int x[ ][] = {{4,3,2}, {7,8,2}, {8,3,10}, {1,2,9}};- What is the order of the array?
- What is the value of x [0] [0] + x [2] [2]?
Consider the following program segment and answer the questions given below:
int x[][]={{2,4,5,6}, {5,7,8,1}, {34,2,10,9}};- What is the position of 34?
- What is the result of x[2][3] + x[1][2]?
Define a class to accept values into a 4 × 4 array and find and display the sum of each row.
Example:
A[][]={1,2,3,4),{5,6,7,8},{1,3,5,7},{2,5,3,1}}
Output:
sum of row 1=10 (1+2+3+4)
sum of row 2=26 (5+6+7+8)
sum of row 3=16 (1+3+5+7)
sum of row 4=11 (2+5+3+1)
