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Question
The number of chiral carbon in glucose is:-
Options
4
5
3
1
MCQ
Solution
4
Explanation:
\[\begin{array}{cc}
\ce{H}\phantom{......}\\
\backslash\phantom{...}\\
\phantom{.....}\ce{C = O}\\
\phantom{}|\\
\phantom{..}\ce{H - C - OH}\\
\phantom{}|\\
\ce{HO - C - H}\phantom{..}\\
\phantom{}|\\
\phantom{..}\ce{H - C - OH}\\
\phantom{}|\\
\phantom{..}\ce{H - C - OH}\\
\phantom{}|\\
\phantom{......}\ce{CH2OH}
\end{array}\]
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