Advertisements
Advertisements
Question
The number of complaints which a bank manager receives per day follows a Poisson distribution with parameter m = 4. Find the probability that the manager receives only two complaints on a given day
Sum
Solution
Let X denote the number of complaints which a bank manager receives per day.
Given, m = 4 and e–4 = 0.0183
∴ X ∼ P(m) = X ∼ p(4)
The p.m.f. of X is given by
P(X = x) = `("e"^-"m" "m"^x)/(x!)`
∴ P(X = x) `("e"^-4(4)^x)/(x!), x` = 0, 1, 2,...
P(only two complaints on a given day)
= P(X = 2)
= `("e"^-4 (4)^2)/(2!)`
= `(0.0183 xx 16)/(2)`
= 0.1464
shaalaa.com
Is there an error in this question or solution?