Question

The number of real value of 'x satisfying `|(x, 3x + 2, 2x - 1),(2x - 1, 4x, 3x + 1),(7x - 2, 17x + 6, 12x - 1)|` = 0 is

Options

• 3

• 0

• More than 3

• 1

Answer 1

0

Explanation:

Applying, R₃ `->` R₃ – (2R₂ + 3R₁) we get

`|(x, 3x + 2, 2x - 1),(2x - 1, 4x, 3x + 1),(0, 0, 0)|` which is equal to zero for all x.