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Question
The numerator of a fraction is 4 less than its denominator. If the numerator is decreased by 2 and the denominator is increased by 1, the denominator becomes eight times the numerator. Find the fraction.
Options
`3/8`
`3/7`
`4/8`
`2/7`
Solution
`3/7`
Explanation:
Let's assume the numerator of the fraction to be x and the denominator of the fraction to be y.
So, the required fraction is `x/y`
From the question it's given as,
The number of the fraction is 4 less the denominator.
Thus, the equation so formed is,
x = y – 4
⇒ x – y = – 4 ......(i)
And also it's given in the question as,
If the numerator is decreased by 2 and denominator is increased by 1, then the denominator is 8 times the numerator.
Putting the above condition in an equation, we get
y + 1 = 8(x – 2)
⇒ y + 1 = 8x – 16
⇒ 8x – y = 1 + 16
⇒ 8x – y = 17 ......(ii)
Solving (i) and (ii),
Substracting the equation (ii) from (ii), we get
(x – y) – (8x – y) = – 4 – 17
⇒ x – y – 8x + y = – 21
⇒ – 7x = – 21
⇒ x = `21/7`
⇒ x = 3
Substituting the value of x = 3 in the equation (i), we find y
3 – y = – 4
⇒ y = 3 + 4
⇒ y = 7
Therefore, the fraction is `3/7`.