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Question
The object function z = 4x1 + 5x2, subject to 2x1 + x2 ≥ 7, 2x1 + 3x2 ≤ 15, x2 ≤ 3, x1, x2 ≥ 0 has minimum value at the point is ______.
Options
on X-axis
on Y-axis
at the origin
on the line parallel to X-axis
MCQ
Fill in the Blanks
Solution
The object function z = 4x1 + 5x2, subject to 2x1 + x2 ≥ 7, 2x1 + 3x2 ≤ 15, x2 ≤ 3, x1, x2 ≥ 0 has minimum value at the point is on X-axis.
Explanation:
The objective function is given as, minimize, z = 4x1 + 5x2
Subject to constraints, 2x1 + x2 ≥ 7, 2x1 + 3x2 ≤ 15, x2 ≤ 3 and x1, x2 ≥ 0
For line 2x1 + x2 = 7
x1 | 0 | 1 | 2 | 3 |
x2 | 7 | 5 | 3 | 1 |
For line 2x1 + 3x2 = 15
x1 | 0 | 3 | 6 |
x2 | 5 | 3 | 1 |
Now, the value of z at comer points are calculated as:
Corner points | z = 4x1 + 5x2 |
A(3.5, 0) | z = 4 × 3.5 + 5 × 0 = 14 (minimum) |
B(7.5, 0) | z = 4 × 7.5 + 5 × 0 = 30 |
C(3, 3) | z = 4 × 3 + 5 × 3 = 27 |
D(2, 3) | z = 4 × 2 + 5 × 3 = 23 |
Hence, the minimum value of z is 14 at point (3.5, 0) which lies on X-axis.
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Linear Inequations in Two Variables
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