English

The object function z = 4x1 + 5x2, subject to 2x1 + x2 ≥ 7, 2x1 + 3x2 ≤ 15, x2 ≤ 3, x1, x2 ≥ 0 has minimum value at the point is ______. -

Advertisements
Advertisements

Question

The object function z = 4x1 + 5x2, subject to 2x1 + x2 ≥ 7, 2x1 + 3x2 ≤ 15, x2 ≤ 3, x1, x2 ≥ 0 has minimum value at the point is ______.

Options

  • on X-axis

  • on Y-axis

  • at the origin

  • on the line parallel to X-axis

MCQ
Fill in the Blanks

Solution

The object function z = 4x1 + 5x2, subject to 2x1 + x2 ≥ 7, 2x1 + 3x2 ≤ 15, x2 ≤ 3, x1, x2 ≥ 0 has minimum value at the point is on X-axis.

Explanation:

The objective function is given as, minimize, z = 4x1 + 5x2

Subject to constraints, 2x1 + x2 ≥ 7, 2x1 + 3x2 ≤ 15, x2 ≤ 3 and x1, x2 ≥ 0

For line 2x1 + x2 = 7

x1 0 1 2 3
x2 7 5 3 1

For line 2x1 + 3x2 = 15

x1 0 3 6
x2 5 3 1


Now, the value of z at comer points are calculated as:

Corner points z = 4x1 + 5x2
A(3.5, 0) z = 4 × 3.5 + 5 × 0 = 14 (minimum)
B(7.5, 0) z = 4 × 7.5 + 5 × 0 = 30
C(3, 3) z = 4 × 3 + 5 × 3 = 27
D(2, 3) z = 4 × 2 + 5 × 3 = 23

Hence, the minimum value of z is 14 at point (3.5, 0) which lies on X-axis.

shaalaa.com
Linear Inequations in Two Variables
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×