English

The objective function Z = x1 + x2, subject to the constraints are x1 + x2 ≤ 10, – 2x1 + 3x2 ≤ 15, x1 ≤ 6, x1, x2 ≥ 0, has maximum value ______ of the feasible region. -

Advertisements
Advertisements

Question

The objective function Z = x1 + x2, subject to the constraints are x1 + x2 ≤ 10, – 2x1 + 3x2 ≤ 15, x1 ≤ 6, x1, x2 ≥ 0, has maximum value ______ of the feasible region.

Options

  • at only one point

  • at only two points

  • at every point of the segment joining two points

  • at every point of the line joining two points equivalent to

MCQ
Fill in the Blanks

Solution

The objective function Z = x1 + x2, subject to the constraints are x1 + x2 ≤ 10, – 2x1 + 3x2 ≤ 15, x1 ≤ 6, x1, x2 ≥ 0, has maximum value at every point of the segment joining two points of the feasible region.

Explanation:

Since, objective function is Z = x1 + x2 and given constraints are

x1 + x2 ≤ 10, – 2x1 + 3x2 ≤ 15, x1 ≤ 6, x1, x2 ≥ 0


Now, the point of intersection oflines x1 + x2 = 10 and – 2x1 + 3x2 = 15 is B(3, 7) and point of intersection of lines x1 = 6 and x1 + x2 = 10 is C(6, 4)

Here, the feasible region is OABCD. The corner points of the feasible region are O(0, 0), A(0, 6), B(3, 7), C(6, 4) and D(6, 0).

At O(0, 0) Z = 0 + 0 = 0
At A(0,6) Z = 0 + 6 = 6
At B(3,7) Z = 3 + 7 = 10
At C(6,4) Z = 6 + 4 = 10
At D(6,0) Z = 6 + 0 = 6

Hence, Z is maximum at each point of the segment joining two points B(3, 7) and C(6, 4)

shaalaa.com
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×