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Question
The order and degree of `(("n + 1")/"n")("d"^4"y")/"dx"^4 = ["n" + (("d"^2"y")/"dx"^2)^4]^(3//5)` are respectively.
Options
4, 5
4, 3
2, 5
4, 2
MCQ
Solution
4, 5
Explanation:
`(("n + 1")/"n")("d"^4"y")/"dx"^4 = ["n" + (("d"^2"y")/"dx"^2)^4]^(3//5)`
`=> [(("n + 1")/"n")("d"^4"y")/"dx"^4]^5 = {["n" + (("d"^2"y")/"dx"^2)^4]^(3//5)}^5`
`=> (("n + 1")/"n")^5(("d"^4"y")/"dx"^4)^5 = ["n" + (("d"^2"y")/"dx"^2)^4]^3`
Here, the highest order derivative is `("d"^4"y")/"dx"^4` with power 5.
∴ order = 4 and degree = 5
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