Question

The order of the differential equation of all circles which lie in the first quadrant and touch both the axes is ______.

Options

• two

• three

• one

• four

Answer 1

The order of the differential equation of all circles which lie in the first quadrant and touch both the axes is one.

Explanation:

Equation of the circle touching both axes is x² + y² - 2ax - 2ay + a² = 0

Here, number of arbitrary constant is one which is equal to the order of its differential equation.