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Question
The oxidation number d-arbitral occupation and co-ordination number of Cr in the complex cis [Cr(en)2Cl2]Cl are respectively.
Options
+3, 3d and 4
+3, 4d and 6
+3, 3d and 6
+2, 3d and 6
MCQ
Solution
+3, 3d and 6
Explanation:
Cr = x + 2(–1) = +1
⇒ x = + 3
Cr+3 has 3d orbitals and a coordination number of 6 in the given complex.
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