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Question
The oxidation state of sulphur in H2S2O7 is ______.
Options
+ 4
+ 6
+ 5
+ 7
MCQ
Fill in the Blanks
Solution
The oxidation state of sulphur in H2S2O7 is + 6.
Explanation:
Let, the oxidation state of sulphur in H2S2O7 be x.
∴ 2(+1) + 2(x) + 7(-2) = 0
2 + 2x - 14 = 0
2x = 12
x = `12/2`
x = + 6
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Chemical Properties of Elements of Groups 16, 17 and 18
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