Question

The pOH of a 0.0235 M hydrochloric acid will be

Options

• 1.629

• 12.37

• 22

• 11.8

Answer 1

12.37

Explanation:

[H⁺] = 0.0235 or 2.35 × 10^–2

pH= – log [H⁺] = – log [2.35 × 10^–2] = l.63

pH + pOH = 14

pOH = 14 – 1.63 = 12.37