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Question
The point A(b, a) lies on the straight line 2x + 3y = 13 and the point B(a, b) lies on the straight line -x + 4y = 5, then the equation of line AB is ______
Options
x - y = 5
x + y = 5
x + y = -5
x - y = -5
MCQ
Fill in the Blanks
Solution
The point A(b, a) lies on the straight line 2x + 3y = 13 and the point B(a, b) lies on the straight line -x + 4y = 5, then the equation of line AB is x + y = 5.
Explanation:
Point A(b, a) is on 2x + 3y = 13
So, 2b + 3a = 13 ........(i)
Point B(a, b) is on -x + 4y = 5
So, 4b - a = 5 .............(ii)
By solving (i) and (ii), we get
a = 3, b = 2
Now, equation of AB is
`y - y_1 = (y_2 - y_1)/(x_2 - x_1)(x - x_1)`
⇒ `y - 3 = (2 - 3)/(3 - 2)(x - 2)`
⇒ y - 2 = -(x - 3)
⇒ x + y = 5
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Equations of Line in Different Forms
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