Question

The point(s) on the curve y = x³ – 11x + 5 at which the tangent is y = x – 11 is/are:

Options

• (–2, 19)

• (2, –9)

• (±2, 19)

• (–2, 19) and (2, –9)

Answer 1

(2, –9)

Explanation:

y = x³ – 11x + 5

`"dy"/"dx"` = 3x² – 11

Slope of line y = x – 11 is 1

3x² – 11 = 1

x = ±2

∴ Point is (2, –9) as (–2, 19) does not satisfy the equation of the given line.