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The probability distribution of a random variable X is given below. If its mean is 4.2, then the values of a and bar respectively X = x 1 2 3 4 5 6 P(X = x) a a a b b 0.3 -

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Question

The probability distribution of a random variable X is given below. If its mean is 4.2, then the values of a and bar respectively 

X = x 1 2 3 4 5 6
P(X = x) a a a b b 0.3

Options

  • 0.3, 0.2

  • 0.1, 0.4

  • 0.1, 0.2

  • 0.2, 0.1

MCQ
Fill in the Blanks

Solution

0.1, 0.2

Explanation:

Since `sum_{x = 1}^6 P(X = x) = 1`,

a + a + a + b + b + 0.3 = 1

⇒ 3a + 2b = 0.7 ....... (i)

Mean = a + 2a + 3a + 4b + 5b + 6 (0.3)

⇒ 4.2 = 6a + 9b + 1.8

⇒ 6a + 9b = 2.4 ........(ii)

On solving (i) and (ii), we get

a = 0.1, b = 0.2

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