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Question
The probability distribution of a random variable X is given below. If its mean is 4.2, then the values of a and bar respectively
X = x | 1 | 2 | 3 | 4 | 5 | 6 |
P(X = x) | a | a | a | b | b | 0.3 |
Options
0.3, 0.2
0.1, 0.4
0.1, 0.2
0.2, 0.1
MCQ
Fill in the Blanks
Solution
0.1, 0.2
Explanation:
Since `sum_{x = 1}^6 P(X = x) = 1`,
a + a + a + b + b + 0.3 = 1
⇒ 3a + 2b = 0.7 ....... (i)
Mean = a + 2a + 3a + 4b + 5b + 6 (0.3)
⇒ 4.2 = 6a + 9b + 1.8
⇒ 6a + 9b = 2.4 ........(ii)
On solving (i) and (ii), we get
a = 0.1, b = 0.2
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