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Question
The probability distribution of the random variable X is given by
X = x | 0 | 1 | 3 | 7 |
P(X = x) | 0.3 | 0.4 | 0.1 | 0.2 |
Then, 4 var (X) - E (X2) is equal to ______
Options
2.24
19.2
15.66
14.96
MCQ
Fill in the Blanks
Solution
The probability distribution of the random variable X is given by
X = x | 0 | 1 | 3 | 7 |
P(X = x) | 0.3 | 0.4 | 0.1 | 0.2 |
Then, 4 var (X) - E (X2) is equal to 15.66.
Explanation:
E(X) = ∑xi . p(xi) = 2.1
`E(X^2) = sumx_i^2 . P(x_i) = 11.1`
Var(X) = `E(X^2) - [E(X)]^2`
= 11.1 - 4.41
= 6.69
Now, 4 var(X) - E(X2) = 4(6.69) - 11.1
= 26.76 - 11.1
= 15.66
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