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The probability distribution of the random variable X is given by X = x 0 1 3 7 P(X = x) 0.3 0.4 0.1 0.2 -

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Question

The probability distribution of the random variable X is given by

X = x 0 1 3 7
P(X = x) 0.3 0.4 0.1 0.2

Then, 4 var (X) - E (X2) is equal to ______ 

Options

  • 2.24

  • 19.2

  • 15.66

  • 14.96

MCQ
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Solution

The probability distribution of the random variable X is given by

X = x 0 1 3 7
P(X = x) 0.3 0.4 0.1 0.2

Then, 4 var (X) - E (X2) is equal to 15.66.

Explanation:

E(X) = ∑xi . p(xi) = 2.1

`E(X^2) = sumx_i^2 . P(x_i) = 11.1`

Var(X) = `E(X^2) - [E(X)]^2`

= 11.1 - 4.41

= 6.69

Now, 4 var(X) - E(X2) = 4(6.69) - 11.1

= 26.76 - 11.1

= 15.66

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