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Question
The quantity which does not vary periodically for a particle performing SHM is ______.
Options
acceleration
total energy
displacement
velocity
Solution
The quantity which does not vary periodically for a particle performing SHM is total energy.
Explanation:
For a particle executing simple harmonic motion (SHM),
Total energy = kinetic energy + potential energy
`= "E"_"K" + "E"_"P" = 1/2 "mv"^2 + 1/2 "kx"^2`
`= 1/"m"("A"^2 - x^2) + 1/2"m"omega^2"A"^2 ....(because "v" = sqrt("A"^2 - x^2) "where, A is the amplitude of the particle")`
`= 1/2 "KA"^2`
t is independent oft, xis remains constant i.e., it does not vary periodically.
However, the displacement of a particle executing SHM along x-axis is given by
x = Asin(ωt + Φ)
(where, A = amplitude, w =angular velocity t = time, Φ = initial phase of the particle)
i.e., displacement varies periodically with time t.
Velocity of particles executing SHM,
v = `"dx"/"dt" = omega sqrt("A"^2 - x^2)`
which varies with x.
Acceleration of the particle,
a = `"dv"/"dt" = - omega^2x`
Which also varies with x.