Question

The radius of the earth and the radius of orbit around the sun are 6371 km and 149 x 10⁶ km respectively. The order of magnitude of the diameter of the orbit is greater than that of earth by ______.

Options

• 10³

• 10²

• 10⁴

• 10⁵

Answer 1

The radius of the earth and the radius of orbit around the sun are 6371 km and 149 x 10⁶ km respectively. The order of magnitude of the diameter of the orbit is greater than that of earth by 10⁴.

Explanation:

Given, radius of earth, R_e = 6371 km and radius of orbit around the sun, R₀ =149 × 10⁶ km

Now, the ratio of the diameters of the earth and orbit around the sun can be expressed as

`"D"_0/"D"_"e" = (2"R"_0)/(2"R"_"e")`

`= (2 xx 14.9 xx 10^6)/(2 xx 6371)`

= 2.33 × 10⁴ 

From above ratio, it can be concluded that the order of magnitude of the diameter of the orbit is greater than that of earth by multiple of 10⁴.