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Question
The radius of the press plunger and pump plunger are in ratio of 50 : 4. If an effort of 20 kgf acts on the pump plunger, calculate the maximum effort which the press plunger can over come.
Solution
Effort acting on the pump plunger = E = 20 kgf
Load acting on the press plunger = L =?
So let radius of pump plunger = 50x = R and radius of press plunger = 4x = r
Now, `"L"/"E"=(π"R"^2)/(π"r"^2)`
`"L"/20=(50"x")^2/(4"x")^2=2500/16=625/4`
L = `625/4xx20`
L = 625 × 5
= 3125 kgf.
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