English

The rate and the rate constants of the reaction, A+2B⟶C+D are 8 × 10−3 mol dm−3 s−1 and 2 × 10−3 s−1 respectively. The concentrations of A and B are 4 mol dm−3 each. -

Advertisements
Advertisements

Question

The rate and the rate constants of the reaction, \[\ce{A + 2B -> C + D}\] are 8 × 10−3 mol dm−3 s−1 and 2 × 10−3 s−1 respectively. The concentrations of A and B are 4 mol dm−3 each. The overall order of the reaction is ____________.

Options

  • 0

  • 1

  • 2

  • 3

MCQ
Fill in the Blanks

Solution

The rate and the rate constants of the reaction, \[\ce{A + 2B -> C + D}\] are 8 × 10−3 mol dm−3 s−1 and 2 × 10−3 s−1 respectively. The concentrations of A and B are 4 mol dm−3 each. The overall order of the reaction is 1.

Explanation:

The rate law is, rate = k[A]x[B]y

where, rate = 8 × 10−3 mol dm−3 s−1,

rate constant k = 2 × 10−3 s−1

Concentration of A = [A] = 4 mol dm−3;

Concentration of B = [B] = 4 mol dm−3

Substituting values in the rate law,

8 × 10−3 M s−1 = 2 × 10−3 s−1 × [4 mol dm−3]x × [4 mol dm−3]y

∴ `(8 xx 10^-3)/(2 xx 10^-3)` = [4]x+y

∴ 4 = [4]x+y

∴ x + y = 1

shaalaa.com
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×