Question

The rate constant for the reaction \[\ce{2H2O5 -> 4NO2 + O2}\] is 30 × 10^–5 sec^–1. if the rate is 204 × 10^–5 mol L^–1 S^–1, then the concentration of N₂O₅ (in mol^–1) is-

Options

• 1.4

• 1.2

• 0.04

• 0.8

Answer 1

0.8

Explanation:

The unit of rate constant (k) indicator reaction to be of first order

r = K[N₂O₅]

= `((2.4 xx 10^5  mol  L^-1  S^-1))/((3.0 xx 10^-55))`

= 0.8