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Question
The rate constant of a first order reaction is 6.9 × 10–3s–1. How much time will it take to reduce the initial concentration to its 1/8th value?
Options
100 s
200 s
300 s
400 s
MCQ
Solution
300 s
Explanation:
[A] = [A]0 `(1/2)^n`
where [A]0 = initial concentration
`1/8 = 1(1/2)^n ; n = 3`
`t^(1/2) = 0.693/(6.9 xx 10^(-3))` = 100 sec
∴ Time = `n xx t_(1/2)` = 3 × 100 = 300 sec.
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