Question

The rate of formation of B at time t for reaction \[\ce{2A -> 3B}\] is equal to ____________.

Options

• `-3/2 ("d"["A"])/("dt")`

• `-2/3 ("d"["A"])/("dt")`

• `-1/3 ("d"["A"])/("dt")`

• `+2 ("d"["A"])/("dt")`

Answer 1

The rate of formation of B at time t for reaction \[\ce{2A -> 3B}\] is equal to `underline(-3/2 ("d"["A"])/("dt"))`.

Explanation:

For the given reaction,

\[\ce{2A -> 3B}\]

Rate = `-1/2 ("d"["A"])/("dt") = 1/3 ("d"["B"])/"dt"`

∴ `("d"["B"])/"dt" = -3/2 ("d"["A"])/("dt")`