Question

The ratio of the weight of a man in a stationary lift and in a lift accelerating downwards with a uniform acceleration α is 3 : 2. The acceleration of the lift is: 

Options

• g/2

• 3g

• 2g

• g/3

Answer 1

g/3

Explanation - 

In a stationary lift, the weight equals milligrammes.

Weight in a downward-accelerating lift = m (g- a)

where a denotes speed

`("mg")/("m"("g" - "a")) = 3/2 => 2"g" = 3"g" - 3"a"`

`"a" = "g"/3`