Advertisements
Advertisements
Question
The ratio of weights of a man inside a lift when it is stationary and when it is going down with a uniform acceleration 'a' is 3 : 2. The value of 'a' will be ______.
(a< g, g = acceleration due to gravity)
Options
`3/2g`
`g/3`
g
`2/3g`
MCQ
Fill in the Blanks
Solution
The ratio of weights of a man inside a lift when it is stationary and when it is going down with a uniform acceleration 'a' is 3 : 2. The value of 'a' will be `underline(g/3)`.
Explanation:
`W_1/W_2=(mg)/(m(g-a))=3/2`
`thereforeg/(g-a)=3/2`
∴ 2g = 3g - 3a
g = 3a
`therefore a = g/3`
shaalaa.com
Is there an error in this question or solution?