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Question
The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction \[\ce{2A + 4B -> 3C + 4D}\], when 5 moles of A react with 6 moles of B, then calculate the amount of C formed?
Solution
Now, the amount of C can be calculated by the limiting reagent, that is, the amount of B.
4 moles of B given 3 moles C. so, the number of moles of C formed by 6 moles of B as follows.
Moles of C = 6 mol of B × `(3 "mol of C")/(4 "mol of B")` = 4.5 mol of C
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