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Question
The regression equation of Y on X is y = `2/9` x and the regression equation of X on Y is `x=y/2+7/6`
Find:
- The correlation coefficient between X and Y.
- `σ_y^2 if σ _x^2=4`
Solution
The repression equation of y on x is y =`2/9x`
Comparing with y − `barY = b_yx (x − barx)`
Here
`b_yx=2/9`
Now the regression eqn. of x on y is x =`y/2+7/6`
Comparing with` x-barx=bxy=1/2`
(a) we have, correlation coefficient between x and y is
`r=sqrt(b_(yx) b_(xy))`
=`sqrt2/9xx1/2=sqrt1/9+-1/3`
∴ `r=1/3 (∵b_(yx) and b_(xy) "are positive")`
`therefore` r = 0.33
(b) `σ_x^2=4⇒ σ_x=2`
We have `b_yx= r.σ_y/σ_x`
∴ `2/9=1/3 σ_y/2`
⇒ `σ_y=12/9`
⇒ `σ_y=4/3`
`therefore ""σ_y^2= 16/9`
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