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Question
The rod given in the figure is made up of two different materials.
Both have square cross-sections of 3 mm side. The resistivity of the first material is 4 x 10-3 Ω.m and it is 25 cm long while the second material has a resistivity of 5 x 10-3 Ω.m and is of 70 cm long. What is the resistivity of rod between its ends?
Solution
Square cross section of side, a = 3 mm = 3 x 10-3 m
Cross section of side, A = a2 = 9 x 106 m
First material:
Resistivity of the material, ρ1 = 4 x 10-3 Ωm
length, l1 = 25 cm = 25 x 10-2 m
Resistance of the lord, R1 = `(rho_1l_1)/"A"`
`= (4xx10^-3 xx 25 xx 10^-2)/(9 xx 10^-6)`
`= (100xx10^-5xx10^6)/9`
R1 = 11.11 x 101 Ω
Second material:
Resistivity of the material, ρ2 = 5 x 10-3 Ωm
length, l2 = 70 cm = 70 x 10-2 m
Resistance of the rod, R2 = `(rho_2l_2)/"A"`
`= (5 xx 10^-3 xx 70 xx 10^-2)/(9 xx 10^-6)`
`= (350 xx 10^-5 xx 10^6)/9`
R2 = 38.88 x 101
R2 = 389 Ω
Total resistance between the ends f the rods
R = R1 + R2 = 111 + 389
= 500 Ω