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The roots of the equation (b – c) x2 + (c – a) x + (a – b) = 0 are equal, then: -

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Question

The roots of the equation (b – c) x2 + (c – a) x + (a – b) = 0 are equal, then:

Options

  • 2a = b + c

  • 2c = a + b

  • b = a + c

  • 2b = a + c

MCQ

Solution

2b = a + c

Explanation:

Since roots are equal.

∴ D = 0 ⇒ b2 – 4ac = 0

⇒ (c – a)2 – 4(b – c) (a – b) = 0

⇒ c2 – b2 – 2ac – 4(ab – b2 + bc) = 0

⇒ c + a – 2b = 0

⇒ c + a = 2b

⇒ c2 + a2 – 2ca – 4ab + 4b2 + 4ac – 4bc = 0

⇒ c2 + a2 + 4b2 + 2ca – 4ab – 4bc = 0

⇒ (c + a – 2b)2 = 0

⇒ c + a – 2b = 0

⇒ c + a = 2b

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