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Question
The roots of the equation (b – c) x2 + (c – a) x + (a – b) = 0 are equal, then:
Options
2a = b + c
2c = a + b
b = a + c
2b = a + c
MCQ
Solution
2b = a + c
Explanation:
Since roots are equal.
∴ D = 0 ⇒ b2 – 4ac = 0
⇒ (c – a)2 – 4(b – c) (a – b) = 0
⇒ c2 – b2 – 2ac – 4(ab – b2 + bc) = 0
⇒ c + a – 2b = 0
⇒ c + a = 2b
⇒ c2 + a2 – 2ca – 4ab + 4b2 + 4ac – 4bc = 0
⇒ c2 + a2 + 4b2 + 2ca – 4ab – 4bc = 0
⇒ (c + a – 2b)2 = 0
⇒ c + a – 2b = 0
⇒ c + a = 2b
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