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Question
The solubility of a solid in a liquid is significantly affected by temperature changes.
\[\ce{Solute + Solvent -> Solution}\]
The system being in a dynamic equilibrium must follow Le-chatelier’s principle.
Considering the Le-chatelier’s principle which of the following is correct?
Options
ΔHsol > 0; solubility ↑; temperature ↓
ΔHsol < 0; solubility ↓; temperature ↑
ΔHsol > 0; solubility ↓; temperature ↑
ΔHsol < 0; solubility ↑; temperature ↓
MCQ
Solution
ΔHsol < 0; solubility ↓; temperature ↑
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