Question

The solubility of CH₃Br_(g) in water is 0.0260 mol/dm³ at 0.164 bar partial pressure and at 25°C. Calculate Henry's law constant.

Answer 1

Given: S = 0.0260 mol/dm³, P = 0.164 bar

∴ K_H = `S/P`

= `(0.0260  "mol dm"^-3)/(0.164  "bar")`

= 0 .159 mol dm⁻³ bar⁻¹