Question

The solubility of N₂ gas in water at 25° C and 1 bar is 6.85 × 10⁻⁴ mol L⁻¹. Calculate K_H (Henry's law constant).

Answer 1

Given: S 6.85 × 10⁻⁴ mol L⁻¹, P = 1 bar, K_H = ?

K_H = ${\displaystyle \frac{S}{P}}$

∴ S = K_H × P

= 6.85 × 10⁻⁴ mol L⁻¹ × 1 bar

∴ S = 6.85 × 10⁻⁴ mol L⁻¹ 1 bar