Question

The solution of the differential equation `(dx)/(dy) + Px = Q` where P and Q are constants or functions of y, is given by

Options

• `xe^(intPdx) = int Qe^(intPdx)  dx + c`

• `ye^(intPdy) = int Qe^(intPdy)  dy + c`

• `ye^(intPdx) = int Qe^(intPdx)  dx + c`

• `xe^(intPdy) = int Qe^(intPdy)  dy + c`

Answer 1

`xe^(intPdy) = int Qe^(intPdy)  dy + c`

Explanation:

I.F = `e^(int pdy)`

Solution is X.I.F = `int Q.I.F  dy + C`

⇒ `xe^(intpdy) = int Q.e^(int pdy)  dy + C`