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Question
The solution of the equation `dx/dy - x = y + 1` is ______
Options
x = cey - y - 2
y = x + cey - 2
x + cey + y - 2 = 0
x - cey + y - 2 = 0
MCQ
Fill in the Blanks
Solution
The solution of the equation `dx/dy - x = y + 1` is x = cey - y - 2
Explanation:
`dx/dy - x = y + 1`
∴ I.F. = `e^{int-1 dy} = e^-y`
∴ solution of the given equation is
`x.e^-y = int(y + 1)e^-y dy + c`
⇒ `xe^-y = e^-y(-y - 2) + c`
⇒ `x = ce^-y - y - 2`
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Solution of a Differential Equation
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