Question

The spin magnetic moment of cobalt in the compound Hg [Co(SCN)₄] is:-

Options

• `sqrt(3)`

• `sqrt(8)`

• `sqrt(15)`

• `sqrt(24`

Answer 1

`sqrt(15)`

Explanation:

The O.N of CO in the complex is

	3d				+2	4s		4d
↑↓	↑↓	↑	↑	↑		↑↓
	3d
↑↓	↑↓	↑	↑	↑

No of unpaired electron (n) = 3

Spin magnetic moment (ms) = `sqrt(n(n + 2))`

`sqrt(3(3 + 2)) = sqrt(15)`