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The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages (in years) was 124. Determine their present ages. - Mathematics

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Question

The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages (in years) was 124. Determine their present ages.

Sum

Solution

Let the present ages of father and his son be x years and (45 – x) years respectively.

Five years ago,

Father's age = (x – 5) years

Son's age = (45 – x – 5) years = (40 – x) years

From the given information, we have:

(x – 5)(40 – x) = 124

40x – x2 – 200 + 5x = 124

x2 – 45x + 324 = 0

x2 – 36x – 9x + 324 = 0

x(x – 36) – 9(x – 36) = 0

(x – 36)(x – 9) = 0

x = 36, 9

if x = 9,

Father's age = 9 years,

Son's age = (45 – x) = 36 years

This is not possible.

Hence, x = 36

Father's age = 36 years

Son's age = (45 – 36) years = 9 years.

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Chapter 6: Solving (simple) Problems (Based on Quadratic Equations) - Exercise 6 (E) [Page 79]

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Selina Mathematics [English] Class 10 ICSE
Chapter 6 Solving (simple) Problems (Based on Quadratic Equations)
Exercise 6 (E) | Q 9 | Page 79

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