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Question
The system of linear equations
3x – 2y – kz = 10
2x – 4y – 2z = 6
x + 2y – z = 5m
is inconsistent if ______.
Options
`k = 3, m = 4/5`
`k ≠ 3, m ∈ R`
`k ≠ 3, m ≠ 4/5`
`k = 3, m ≠ 4/5`
Solution
The system of linear equations
3x – 2y – kz = 10
2x – 4y – 2z = 6
x + 2y – z = 5m
is inconsistent if `underlinebb(k = 3, m ≠ 4/5)`.
Explanation:
Given: System of linear equations
3x – 2y – kz = 10
2x – 4y – 2z = 6
x + 2y – z = 5m
is inconsistent.
Form determinant D with coefficients of x, y, z.
Dx is formed by replacing coefficients of x with constant terms.
Dy is formed by replacing coefficients of y with constant terms.
Dz is formed by replacing coefficients of z with constant terms.
For, the equation to be inconsistent,
D = `|(3, -2, -k),(2, -4, -2),(1, 2, -1)|` = 0
⇒ 3(4 + 4) + 2(–2 + 2) – k(4 + 4) = 0
⇒ k = 3
Also, at least one of Dx, Dy, Dz must be non-zero.
Dx = `|(10, -2, -3),(6, -4, -2),(5m, 2, -1)|` ≠ 0
⇒ 10(4 + 4) + 2(–6 + 10m) – 3(12 + 20m) ≠ 0
⇒ 80 – 12 + 20m – 36 – 60 m
⇒ 40m ≠ 32
⇒ `m ≠ 4/5`
Dy = `|(3, 10, -3),(2, 6, -2),(1, 5m, -1)|`
= `-|(3, 10, 3),(2, 6, 2),(1, 5m, 1)|` = 0 ...(∵ Two columns of Dy are same)
Dz = `|(3, -2, 10),(2, -4, 6),(1, 2, 5m)|` ≠ 0
⇒ 3(–20m – 12) + 2(10m – 6) + 10(4 + 4) – 40m + 32 ≠ 0
⇒ `m ≠ 4/5`