Advertisements
Advertisements
Question
The tangent and the normal at a point P on an ellipse `x^2/a^2 + y^2/b^2` = 1 meet its major axis in T and T' so that TT' = a then e2cos2θ + cosθ (where e is the eccentricity of the ellipse) is equal to ______.
Options
1
`1/2`
`2/3`
`1/4`
Solution
The tangent and the normal at a point P on an ellipse `x^2/a^2 + y^2/b^2` = 1 meet its major axis in T and T' so that TT' = a then e2cos2θ + cosθ (where e is eccentricity of the ellipse) is equal to 1.
Explanation:
Let the eccentric angle of the point P be θ so that tangent is `(xcosθ)/a + (ysinθ)/b` = 1 ...(i)
and normal is `(ax)/cosθ - (by)/sinθ` = a2 – b2 ...(ii)
These lines meet the major axis y = 0 at points T and T' such that TT' = a
So T is `(a/cosθ, 0)` and T' is `(((a^2 - b^2)cosθ)/a, 0)`
∴ TT' is `a/cosθ - ((a^2 - b^2)cosθ)/a` = a (given)
or a2 – a2e2cos2θ = a2cosθ
or 1 – e2cos2θ = cosθ
or e2cos2θ + cosθ – 1 = 0
or e2cos2θ + cosθ = 1