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The term independent of x in the expansion of (x6-1x3)9 is ______. -

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Question

The term independent of x in the expansion of `(root(6)(x) - 1/root(3)(x))^9` is ______.

Options

  • 9C3

  • 9C4

  • 9C5

  • 8C3

MCQ
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Solution

The term independent of x in the expansion of `(root(6)(x) - 1/root(3)(x))^9` is `underlinebb(- ""^9C_3)`.

Explanation:

Tr + 1 = `""^9C_r (root(6)(x))^(9 - r) (-1/root(3)(x))^r`

= `""^9C_r (-1)^r . x^((9 - r)/6 - r/3)`

= `""^9C_r . x^(((9 - 3r)/6))`

Now `(9 - 3r)/6` = 0 `\implies` r = 3 ;

Thus, term independent of x = – 9C3

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Middle term(s) in the expansion of (a + b)n
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