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Question
The time taken by a person to cover 150kms was 2.5 hrs more than the time taken in the return j ourney. If he returned at a speed of 10km/ h more than the speed when going, find his speed per hour in each direction.
Solution
Let the speed of the person be S, Hence return speed of the person = S +10.
D=150 Km, Time = Distance / Speed. Time difference= 2.5 Hours
Hence, in these two conditions,
`150/"S" - 150/("S" + 10) = 2.5`
⇒ 150 x (S+10) - 150 x S= S x (S+10) x 2.5
⇒ 2.5 s2 + 25 s - 1500 = 0
⇒ 25 s2+ 250 s - 15000 = 0
⇒ S2 + 10 S - 600 = 0
⇒ S2 + 30S - 20S - 600 = 0
⇒ S (S+30) - 20 (S + 30) = 0
⇒ (S+30) (S - 20) = 0
As the speed can't be negative, S = 20km/ hr and while return, its 30km/ hr
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