Question

The titanium (Z = 22) compound that does not exist is:-

Options

• TiO

• TiO₂

• K₂TiF₆

• Ticl₃

Answer 1

K₂TiF₆ 

Explanation:

Ti (Z = 22) has configuration [Ag]8³d48² it can show +1, +2, +3, +4.

In K₂TiO₄: Oxidation state of Ti = +6 therefore, it does not exist.