Advertisements
Advertisements
Question
The total energy of the body executing S.H.M. is E. The kinetic energy of the body, when the displacement is half of the amplitude is ______.
Options
`"E"/2`
`"E"/4`
`(3"E")/4`
`sqrt3/4` E
MCQ
Fill in the Blanks
Solution
The total energy of the body executing S.H.M. is E. The kinetic energy of the body, when the displacement is half of the amplitude is `underlinebb((3"E")/4)`.
Explanation:
E = `1/2"m"omega^2"A"^2 ⇒ "K" = 1/2"m"omega^2("A"^2 - "A"^2/4)`
= `3/4(1/2"m"omega^2"A"^2) = 3/4"E"`
shaalaa.com
Amplitude (A), Period (T) and Frequency (N) of S.H.M.
Is there an error in this question or solution?
