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The total number of α and β particles emitted in the nuclear reaction A92238A2922238U⟶A82214A2822214Pb is ______. -

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Question

The total number of α and β particles emitted in the nuclear reaction \[\ce{^238_92U -> ^214_82Pb}\] is ______.

Options

  • 2

  • 4

  • 6

  • 8

MCQ
Fill in the Blanks

Solution

The total number of α and β particles emitted in the nuclear reaction \[\ce{^238_92U -> ^214_82Pb}\] is 8.

Explanation:

α = `(238 - 214)/4 = 24/4` = 6

β = 82 – (92 – 6 × 2) = 82 – 80 = 2

∴ α + β = 6 + 2 = 8

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Limitations of Rutherford’s Atomic Model
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