Question

The total number of possible isomers of the complex compound [Cu^II(NH₃)₄][Pt^IICl₄] is ______.

Options

• 3

• 6

• 5

• 4

Answer 1

The total number of possible isomers of the complex compound [Cu^II(NH₃)₄][Pt^IICl₄] is 4.

Explanation:

For [Cu^II(NH₃)₄][Pt^IICl₄] four isomers are possible which are [Cu(NH₃)₄][PtCl₄], [CuCl₄][Pt(NH₃)₄], [PtCl₃(NH₃)] [Cu(NH₃)₃Cl] and [Pt(NH₃)₃Cl] [Cu(NH₃)Cl₃].