Question

The total weight of a piece of wood is 6 kg. In the floating state in water its `1/3` part remains inside the water. On this floating piece of wood what maximum weight is to be put such that the whole of the piece of wood is to be drowned in the water?

Options

• 15 kg

• 14 kg

• 10 kg

• 12 kg

Answer 1

12 kg

Explanation:

Weight of submerged part of the block

W = `1/3`v (Density of water) g          ...(i)

Excess weight, = wight of water having `2/3` volume of the block.

W' = `2/3`v  (Density of water) g          ...(ii)

Dividing (ii) by (i)

`"W'"/"W"=(2//3)/(1//3)`

∴ W' = 2W

⇒ W' = 2 × 6 = 12 kg