Question

The trajectories of the two projectiles are shown in the figure. Let T₁ and T₂ be the time periods and u₁ and u₂ be their speeds of projection. Then ______.

 

Options

• T₂ > T₁

• T₁ > T₂

• u₁ > u₂

• u₁ < u₂

Answer 1

The trajectories of the two projectiles are shown in the figure. Let T₁ and T₂ be the time periods and u₁ and u₂ be their speeds of projection. Then u₁ < u₂.

Explanation:

∴ Both projectiles have equal height,

H = `(u^2sin^2theta)/(2g) = (u_y^2)/(2g)`

∴ Time of flight of both will be the same,

T₁ = T₂ = `(2usintheta)/g = (2u_y)/g`

Since Range is greater for the second.

∴ R₂ > R₁ Thus `(u_x)_2 > (u_x)_1`

So, u₂ > u₁