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Question
The value of cot `(tan^-1 2x + cot^-1 2x)` is ______
Options
0
2x
π + 2x
π - 2x
MCQ
Fill in the Blanks
Solution
The value of cot `(tan^-1 2x + cot^-1 2x)` is 0.
Explanation:
`cot(tan^-1 2x + cot^-1 2x) = cot(pi/2) = 0`
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