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The value of ddx[tan-1(a-x1+ax)] is ______. -

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Question

The value of `d/(dx)[tan^-1((a - x)/(1 + ax))]` is ______.

Options

  • `- 1/(1 + x^2)`

  • `1/(1 + a^2) - 1/(1 + x^2)`

  • `1/(1 + x^2)`

  • None of these

MCQ
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Solution

The value of `d/(dx)[tan^-1((a - x)/(1 + ax))]` is `underlinebb(- 1/(1 + x^2))`.

Explanation:

`d/(dx)[tan^-1((a - x)/(1 + ax))]`

= `d/(dx) (tan^-1a - tan^-1x)`

= `0 - 1/(1 + x^2)`

= `-1/(1 + x^2)`

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