Question

The value of K_c is 64 at 800 K for the reaction \[\ce{N2(g) + 3H2(g) <=> 2NH3(g)}\].

The value of K_c for the following reaction is:

\[\ce{NH3(g) <=> 1/2N2(g) + 3/2H2(g)}\]

Options

• `1/64`

• 8

• `1/4`

• `1/8`

Answer 1

`bb(1/8)`

Explanation:

\[\ce{N2(g) + 3H2(g) <=> 2NH3(g)}\]; K_c

\[\ce{2NH3(g) <=> N2(g) + 3H2(g)}\]; `1/"K"_"c"`

\[\ce{NH3(g) <=> 1/2N2(g) + 3/2H2(g)}\]; `1/("K"_"c"^(1//2))`

`1/("K"_"c"^(1//2)) = 1/((64)^(1//2)) = 1/8`