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Question
The value of tan A + sin A = M and tan A - sin A = N.
The value of `("M"^2 - "N"^2) /("MN")^0.5`
Options
4
3
2
1
MCQ
Solution
4
Explanation:
`"M"^2 - "N"^2 = ("Tan A" + "Sin A" + "Tan A" - "Sin A") ("Tan A" + "Sin A" - "Tan A" + "Sin A")`
`"M"^2 - "N"^2 = 4 "tan A sin A"`
and `("MN")^0.5 = ("tan"^2 "A" - "sin"^2 "A")^ 0.5`
`("MN")^0.5 = "sin A" [(1/("cos"^2 "A")) - 1]^0.5`
`("MN")^0.5 = "tan A sin A"`
Therefore, `("m"^2 - "n"^2)/("mn")^0.5` = 4
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